For the equilibrium A B ( g ) ⇌ A ( g ) + B ( g ) , at a given temperature 1 3 r d of AB is dissociated then P K p will be numerically equal to

Σ n = 2 3 + 2 3 + 1 3 = 4 3 K p = n A × n B n A B × P Σ n Δ n g = 1 3 × 1 3 2 3 × P 4 3 1 = 1 6 × 3 P 4 = P 8 So, P K p = 8

Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

For the equilibrium $A B (g) ⇌ A (g) + B (g)$ , at a given temperature $\frac{1}{3} r d$ of AB is dissociated then $\frac{P}{K_{p}}$ will be numerically equal to

Answer:

8.00

Solution:

$Σ n = \frac{2}{3} + \frac{2}{3} + \frac{1}{3} = \frac{4}{3}$
$K_{p} = \frac{n_{A} \times n_{B}}{n_{A B}} \times {(\frac{P}{Σ n})}^{Δ n_{g}}$
$= [\frac{\frac{1}{3} \times \frac{1}{3}}{\frac{2}{3}}] \times {[\frac{P}{\frac{4}{3}}]}^{1}$
$= \frac{1}{6} \times \frac{3 P}{4} = \frac{P}{8}$
So, $\frac{P}{K_{p}} = 8$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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