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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

For the reaction, $N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)$ the degree of dissociation at equilibrium is 0.4 at a pressure of 1 atm. The value of $K_{p}$ is

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Answer:

Solution:

$K_{p} = \frac{{(P_{N O^{2}})}^{2}}{(P_{N_{2} O_{4}})} = \frac{4 α^{2}}{1 - α^{2}} \times P$
$\Rightarrow K_{p} = \frac{4 \times {(0.4)}^{2}}{1 - {(0.4)}^{2}} \times 1$
$∴ K_{p} = 0.762 a t m$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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