Chemistry - Chemical Equilibrium Question with Solution | TestHub

$\text{C}{\text{u}}^{2+}$ions will react with$\text{C}{\text{N}}^{-}$and$\text{SC}{\text{N}}^{-}$forming$\left[\text{Cu}\right(\text{CN}{)}_4{]}^{3-}$and$\left[\text{Cu}\right(\text{SCN}{)}_4{]}^{3-}$leading the reaction in the backward direction.

$\text{C}{\text{u}}^{2+}+\text{2C}{\text{N}}^{-}\to \text{Cu}{\left(\mathrm{C}\mathrm{N}\right)}_2$

$\text{2Cu}(\text{CN}{)}_2\to \text{2CuCN}+{\left(\mathrm{C}\mathrm{N}\right)}_2$

$\text{CuCN}+\text{3C}{\text{N}}^{-}\to [\text{Cu}{\left(\text{CN}{)}_4\right]}^{3-}$

$\text{C}{\text{u}}^{2+}+\text{4SC}{\text{N}}^{-}\to [\text{Cu}{\left(\text{SCN}{)}_4\right]}^{3-}$

$\text{C}{\text{u}}^{2+}$also combines with$\text{CuC}{\text{l}}_2$which reacts with Cu to produce CuCl pushing the reaction in the backward direction.

$\text{CuC}{\text{l}}_2+\text{Cu}\to \text{2CuCl}\downarrow$