Chemistry - Chemical Equilibrium Question with Solution | TestHub

${\text{K}}_{\text{p}}=\frac{{\left[{\text{P}}_{{\text{NO}}_{\text{2}}}\right]}^2}{{\text{P}}_{{\text{N}}_2{\text{O}}_{\text{4}}}}$

${\text{K}}_{\text{p}}=\frac{\text{4}{\alpha }^2}{1-{\alpha }^2}\text{p}$

$\Rightarrow {\text{K}}_{\text{p}}=\frac{4\times {\left(0.2\right)}^2}{1-{\left(0.2\right)}^2}=\frac{0.16}{0.96}$

$\text{for}2{\text{NO}}_2\stackrel{}{\rightleftharpoons }{\text{N}}_{\text{2}}{\text{O}}_4;{\text{K}}_{\text{p}}=\frac{0.96}{0.16}=6$