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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumLe-Chatelier's PrincipleMedium2 minQB
ChemistryMediummatching list

Match List-I having reaction with List-II having conditions.

List - I

(Consider all dissociation reactions are endothermic & association reactions are exothermic)

List - II

(P)

(1) Extent of reaction will not increase with increase in pressure

(Q)

(2) Concentration of products will increase with increase in temperature.

(R)

(3) Increase in volume will increase moles of reactant

(S)

(4) Introduction of inert gas at constant pressure will shift equilibrium to the product side.

Options:

Answer:
C
Solution:

Question Explanation: Match reversible reactions with equilibrium shifts under varied conditions.

Concept: Le-Chatelier's Principle for pressure, temperature, and volume. Solution:

 

= Moles of gaseous products – Moles of gaseous reactants.

⇒If , an inert gas (at constant P) shifts equilibrium forward.

⇒If , pressure has no effect on the equilibrium position. ⇒Endothermic reactions () shift forward with a temperature increase.

Reaction (P): ;Endothermic. High temperature favors products (2). High volume/low pressure favors more gas moles (reactant side), increasing moles of A (3).

Reaction (Q): .Endothermic. Pressure has no effect on extent(1). High temperature favors products (2).

Reaction (R): association (Exothermic). High volume favors more gas moles (reactant side), increasing moles of A (3).

Reaction (S): Dissociation (Endothermic). High pressure favors fewer moles (reactant), so the extent does not increase with pressure (1). High temperature favors products (2). An inert gas at constant pressure favors the side with more moles (product side) (4).

 

 

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Le-Chatelier's Principle
2mℹ️ Source: QB

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