Chemistry - Chemical Equilibrium Question with Solution | TestHub

$\begin{array}{rl}{\mathrm{K}}_{\mathrm{p}}& ={\mathrm{K}}_{\mathrm{c}}[\mathrm{RT}{]}_{\mathrm{g}}^{\Delta \mathrm{n}}\Delta \mathrm{n}=2-4=-2\\ \mathrm{T}& =673\mathrm{K},{\mathrm{K}}_{\mathrm{c}}=0.5\\ \mathrm{R}& =0.082\mathrm{L}\cdot \mathrm{atm}\cdot {\mathrm{mol}}^{-1}{\mathrm{K}}^{-1}\\ {\mathrm{K}}_{\mathrm{p}}& =0.5\times (0.082\times 673{)}^{-2}\\ & =1.64\times 10^{-4}\mathrm{atm}\end{array}$