Chemistry - Chemical Equilibrium Question with Solution | TestHub

$\log \frac{{\mathrm{k}}_2}{{\mathrm{k}}_1}=\frac{\text{Δ}\mathrm{H}}{2.303\mathrm{K}}(\frac{1}{{\mathrm{T}}_1}-\frac{1}{{\mathrm{T}}_2})$

$\therefore \text{Δ}\mathrm{H}=-\mathrm{ve}$and for the maximum formation of the product${\mathrm{k}}_2>{\mathrm{k}}_1$hence,${\mathrm{T}}_1>{\mathrm{T}}_2$mean temperature should decrease

$\text{Δ}{\mathrm{n}}_{\mathrm{g}}=-\mathrm{ve}$

${\mathrm{k}}_{\mathrm{p}}\propto \frac{1}{\mathrm{p}}$on increasing$\mathrm{p}$reaction goes in forward direction.