Chemistry - Chemical Equilibrium Question with Solution | TestHub

${\text{K}}_{{\text{P}}_{\text{1}}}\text{=}\frac{{\text{p}}_{{\text{NH}}_{\text{3}}}^{\text{2}}}{{\text{p}}_{{\text{N}}_{\text{2}}}{\text{.p}}_{{\text{H}}_{\text{2}}}^{\text{3}}}$...(i)

${\text{K}}_{{\text{P}}_{\text{2}}}\text{=}\frac{{\text{P}}_{{\text{NH}}_{\text{3}}}}{{\text{p}}_{{\text{N}}_{\text{2}}}^{\frac{\text{1}}{\text{2}}}{\text{.p}}_{{\text{H}}_{\text{2}}}^{\frac{\text{3}}{\text{2}}}}$

${\text{K}}_{{\text{P}}_{\text{2}}}^{\text{2}}\text{=}\frac{{\text{p}}_{{\text{NH}}_{\text{3}}}^{\text{2}}}{{\text{p}}_{{\text{N}}_{\text{2}}}{\text{.p}}_{{\text{H}}_{\text{2}}}^{\text{3}}}$...(ii)

Dividing equation (ii) by equation (i)

$\frac{{\text{K}}_{{\text{P}}_{\text{1}}}}{{\text{K}}_{{\text{P}}_{\text{2}}^{\text{2}}}}\text{=1}$

or${\text{K}}_{{\text{P}}_{\text{1}}}\text{=}{\text{K}}_{{\text{P}}_{\text{2}}}^{\text{2}}$