Chemistry - Chemical Equilibrium Question with Solution | TestHub

${\mathrm{N}}_2{\mathrm{O}}_4\rightleftharpoons 2{\mathrm{NO}}_2$ $\begin{array}{lcc}\text{ Initially }& 1& 0\\ \text{ At equilibrium }& 1-\alpha & 2\alpha \end{array}$ ${\mathrm{N}}_2{\mathrm{O}}_4$ is $50\%$ dissociated, so $\alpha =\frac{1}{2}$ $K_p=\frac{p_{{\mathrm{NO}}_2}^2}{p_{{\mathrm{N}}_2{\mathrm{O}}_4}}=\frac{{\left(2\times \frac{1}{2}\right)}^2}{\left(1-\frac{1}{2}\right)}=2\mathrm{atm}$