Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

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For the reaction $N_{2} (g) + O_{2} (g) ⇌ 2 N O (g),$ the value of $K_{c}$ at 800 $° C$ is 0.1. What is the value of $K_{P}$ at this temperature?

Answer:

Solution:

$N_{2} (g) + O_{2} (g) ⇌ 2 N O (g);$ $K_{c} = 0.1$
$Δ n_{g} = 2 - 2 = 0$
$K_{p} = K_{c} (R T)^{Δ n_{g}}$
As $Δ n_{g} = 0,$ hence $K_{P} = K_{c}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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