Chemistry - Chemical Equilibrium Question with Solution | TestHub

$\alpha$-D glucose $\rightleftharpoons \beta$-D glucose $\begin{array}{lcc}\text{ Initial }& 1& 0\\ \text{ At equilibrium }& 1-\alpha & \alpha \end{array}$ $K=\frac{\alpha }{1-\alpha }=1.8$ Solving $\alpha =0.642$ $1-\alpha =0.358$ Percent of $\alpha$-D glucose remaining at equilibrium $=35.8\%$.