The value of equilibrium constant of the reaction HI ( g ) ⇌ 2 1 H 2 ( g ) + 2 1 I 2 is 8.0 The equilibrium constant of the reaction H 2 ( g ) + I 2 ( g ) ⇌ 2 HI ( g ) will beNEET 2008 (Mains)

HI ⇌ 2 1 H 2 + 2 1 I 2 , K 1 = 8.0 or 2 HI ⇌ H 2 + I 2 , K 2 = 64 or H 2 + I 2 ⇌ 2 HI , K 3 = 64 1

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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2008

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The value of equilibrium constant of the reaction $HI (g) ⇌ \frac{1}{2} H_{2} (g) + \frac{1}{2} I_{2} is 8.0$ The equilibrium constant of the reaction $H_{2} (g) + I_{2} (g) ⇌ 2 HI (g)$ will beNEET 2008 (Mains)

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Solution:

$HI ⇌ \frac{1}{2} H_{2} + \frac{1}{2} I_{2}, K_{1} = 8.0$ or $2 HI ⇌ H_{2} + I_{2}, K_{2} = 64$ $or H_{2} + I_{2} ⇌ 2 HI, K_{3} = \frac{1}{64}$

Stream:NEETSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2008

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