Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGVBT(overlapping & Hybridisation)Medium2 minQB
ChemistryMediuminteger

Find the total number of CORRECT statements out of following :-

 

(i) Orbitals having large energy difference of an element can participate in hybridisation

(ii) In all bond lengths are not identical

(iii) dipole moment of is more than

(iv) all allotropes of carbon have same hybridisation of each carbon atom

Answer:
1
Solution:

(i) Incorrect — Hybridization occurs between orbitals having comparable energies. Orbitals with a large energy difference do not effectively hybridize.

(ii) Correct — XeO₂F₂ has a see-saw geometry (AX₄E). Due to different ligands (O and F) and their positions, all Xe–O/Xe–F bond lengths are not identical. (iii) Incorrect — CCl₄ is tetrahedral and symmetrical, hence

while NF₃ has a non-zero dipole moment. Therefore, CCl₄ does not have a greater dipole moment. (iv) Incorrect — Different carbon allotropes have different hybridization: Diamond → sp³, Graphite → sp², Fullerene → sp².

Hence, only (ii) is correct.

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VBT(overlapping & Hybridisation)
2mℹ️ Source: QB

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