Consider following molecular species : XeF₄, ClO₄⁻, XeO₃, IF₄⁺, ClF₃, SF₆, SF₄, PCl₆⁻, XeO₆⁴⁻, S₃O₆²⁻. Calculate z ( x + y ) . Here, x = total number of molecular species in which all bond lengths a

Question

Consider following molecular species :

XeF₄, ClO₄⁻, XeO₃, IF₄⁺, ClF₃, SF₆, SF₄, PCl₆⁻, XeO₆⁴⁻, S₃O₆²⁻.

Calculate $\frac{( x + y )}{z}$ .

Here, $x$ = total number of molecular species in which all bond lengths are not equal.

$y$ = total number of species in which 'd' orbital (having zero nodal planes) participates in hybridization.

$z$ = total number of planar species.

TestHub · Accepted Answer

Values of x , y , and z : x = 4 : Species with unequal bond lengths (axial  = equatorial) are IF₄⁺, ClF₃, SF₄, and PCl₅. y = 7 : The d -orbital with zero nodal planes is d z 2 ​ , which participates in sp³d and sp³d² hybridizations found in XeF₄, IF₄⁺, ClF₃, SF₆, SF₄, PCl₅, and XeO₆⁴⁻. z = 2 : The planar species are XeF₄ (square planar) and ClF₃ (T-shaped). Calculation: z x + y ​ = 2 4 + 7 ​ = 5.50

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