AB is a polar molecule It's bond length is $5$ Å. If the maximum dipole moment of the molecule is $b \times 1 0^{- 29}$ coulomb meter, what is the value of '100b'?
[Assume charge of electron $= 1.602 \times 1 0^{- 19}$ coulomb]

Question

AB is a polar molecule It's bond length is $5$ Å. If the maximum dipole moment of the molecule is $b \times 1 0^{- 29}$ coulomb meter, what is the value of '100b'?

[Assume charge of electron $= 1.602 \times 1 0^{- 19}$ coulomb]

TestHub · Accepted Answer

μ m a x ​ = q × d = 1.602 × 1 0 − 19 × 5 × 1 0 − 10 = 8.01 × 1 0 − 29 coulomb meter = b × 1 0 − 29 ∴ 100 b = 801

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