Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGVBT(overlapping & Hybridisation)Medium2 minQB

ChemistryMediumsingle choice

The hybridization of atomic orbitals of nitrogen in $NO_{2}^{+}$ , $NO_{3}^{-}$ and $NH_{4}^{+}$ are

Answer:

Solution:

Concepts: Steric number (SN) determines hybridization. SN = (number of sigma bonds) + (number of lone pairs).

NO₂⁺: SN = 2 (2 sigma bonds, 0 lone pairs) $\to$ sp

NO₃⁻: SN = 3 (3 sigma bonds, 0 lone pairs) $\to$ sp²

NH₄⁺: SN = 4 (4 sigma bonds, 0 lone pairs) $\to$ sp³

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VBT(overlapping & Hybridisation)

⏱ 2mℹ️ Source: QB

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