Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Explain Question :

Calculate the bond angle difference between the anionic parts of solid ${\mathrm{I}}_2$ and solid ${\mathrm{N}}_2{\mathrm{O}}_5$.

Concept : This question is based on structure of ionic solids and VSEPR theory.

Solution : ${\mathrm{I}}_3^{\ominus }$ ${\mathrm{NO}}_3^{\ominus }$

$180^{\circ }$ $120^{\circ }$

Angle difference is $60^{\circ }$.

Final answer : $60^{\circ }$