Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(i) Solid HF forms a zigzag chain structure with an F-H⋅⋅⋅F angle close to $120^{\circ }$ at fluorine, not a flat alternating alignment.

(ii) H₂O₂ has a non-planar "open-book" geometry in all states, rather than being completely planar.

(iii) H₂Se consists of pure $p$-orbitals participating in bonding due to Drago's rule, making its bond angle approximately $91^{\circ }$, not $106^{\circ }$.

(iv) P₄ (white phosphorus) possesses a tetrahedral cage structure with a $60^{\circ }$ bond angle instead of a square planar ring.

(v) Nitrile groups ($-C\equiv N$) feature $sp$-hybridized carbons, which must be completely linear ($180^{\circ }$) with the benzene ring instead of being bent at $90^{\circ }$.