CHEM_REMOVED - CHEMICAL BONDING Question with Solution | TestHub

In case of $\mathrm{N}{\left({\mathrm{SiH}}_3\right)}_3\mathrm{N}$ atom is $s{p}^2$ hybridised, the lone pair is present in $2p$ orbital and it is transferred to empty $d$ orbital of Si forming $d\pi -p\pi$ bond. Hence nitrogen with $s{p}^2$ hybridization has trigonal planar shape.