Find out total number of combination of atomic orbitals, which form $π$ -bond when orbital overlap along y axis.
(i) $p_{y} + p_{y}$ (ii) $d_{xy} + d_{xy}$
(iii) $p_{x} + p_{x}$ (iv) $d_{xy} + p_{x}$
(v) $d_{x y} + d_{x^{2} - y^{2}}$ (vi) $d_{xz} + d_{xy}$
(vii) $p_{z} + d_{xz}$

Question

Find out total number of combination of atomic orbitals, which form $π$ -bond when orbital overlap along y axis.

(i) $p_{y} + p_{y}$ (ii) $d_{xy} + d_{xy}$

(iii) $p_{x} + p_{x}$ (iv) $d_{xy} + p_{x}$

(v) $d_{x y} + d_{x^{2} - y^{2}}$ (vi) $d_{xz} + d_{xy}$

(vii) $p_{z} + d_{xz}$

TestHub · Accepted Answer

A pi ( π ) bond forms from the sideways overlap of atomic orbitals. For overlap along the y-axis, the orbitals must have the correct orientation to form a π bond. (i) p y ​ + p y ​ : Forms a sigma ( σ ) bond along the y-axis. (ii) d x y ​ + d x y ​ : Forms a π bond. (iii) p x ​ + p x ​ : Forms a π bond. (iv) d x y ​ + p x ​ : Forms a π bond. (v) d x y ​ + d x 2 − y 2 ​ : No effective overlap, forms a non-bonding interaction. (vi) d x z ​ + d x y ​ : No effective overlap, forms a non-bonding interaction. (vii) p z ​ + d x z ​ : No effective overlap, forms a non-bonding interaction. Therefore, combinations (ii), (iii), and (iv) form π bonds. Total number of combinations forming π bonds = 3.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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JEE Advanced 2027 (Class 12+)