Molecular orbital energy level diagram for $H_{2}$ molecule is as follows :
If Δ = 17500 cm^-1 then select the correct option(s) (Given : 1 K Cal mol^-1 = 350 cm^-1 )

Question

Molecular orbital energy level diagram for H 2 ​ molecule is as follows : If Δ = 17500 cm -1 then select the correct option(s) (Given : 1 K Cal mol -1 = 350 cm -1 )

TestHub · Accepted Answer

The energy difference between LUMO and HOMO is $2Δ$ , as shown by the two intervals of $Δ$ separating the molecular orbitals. Substituting $Δ = 17500 c m^{- 1}$ gives an energy difference of $2 \times 17500 = 35000c m^{- 1}$ (Option D).

The bond energy of H₂ equals the total stabilization energy of its two electrons in the bonding molecular orbital, which is also $2Δ$ . This gives a total stabilization energy of $2 \times 17500 = 35000 c m^{- 1}$ . Converting this energy using the given factor ( $1 K C a l m o l^{- 1} = 350 c m^{- 1}$ ) yields $\frac{35000}{350} = 100KCalmo l^{- 1}$ (Option B).

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Options:(select one or more)

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