Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Percentage polarity $=\frac{\text{ observed dipolemoment of molecules }\times 100}{\text{ calculateddipole moment }}\%$

Here observed dipole moment of $\mathrm{HCl}=1.03\mathrm{D}$

Calculated dipole moment of$\mathrm{HCl}=4.8\times 10^{-10}\times 1.275\times 10^{-8}=4.8\times 1.275\mathrm{D}$

Therefore, % polarity $=\frac{1.03}{4.8\times 1.275}\times 100\%$.