Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGVSEPR, Bond Angle, Bond Length, Bond EnergyMedium2 minQB
ChemistryMediummultiple choice

Select the species in which one of the ions contains atleast 4 atoms in same plane.

Options:(select one or more)

Answer:
A, B, D
Solution:

 

The question asks to identify species where at least one ion contains at least 4 atoms in the same plane. We need to analyze the ionic structures of the given compounds.

A. N₂O₄(s) exists as [NO⁺][NO₃⁻] in the solid state. The nitrate ion, NO₃⁻, is trigonal planar, with 4 atoms (1 N, 3 O) in the same plane.

B. XeF₆(s) exists as [XeF₅⁺][F⁻] or [XeF₄²⁺][2F⁻] or [XeF₃⁺][XeF₃F₂⁻] in solid state. The XeF₅⁺ ion has a square pyramidal geometry. The Xe atom and the four basal F atoms lie in the same plane, making 5 atoms in the same plane.

C. PBr₅(s) exists as [PBr₄⁺][Br⁻] in the solid state. The PBr₄⁺ ion is tetrahedral, so no 4 atoms lie in the same plane.

D. I₂Cl₆(l) exists as a dimer in the liquid state, but in the solid state, it can exist as [ICl₂⁺][ICl₄⁻]. The ICl₄⁻ ion has a square planar geometry, with 5 atoms (1 I, 4 Cl) in the same plane.

Therefore, options A, B, and D contain an ion with at least 4 atoms in the same plane.

The final answer is .

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VSEPR, Bond Angle, Bond Length, Bond Energy
2mℹ️ Source: QB

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