Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(A) F–F > O–O > N–N (Wrong)

Actual bond strength: N–N > O–O > F–F

Reason: Lone pair repulsion is highest in F–F → weakest bond.

(B) 2pπ–2pπ > 2pπ–3pπ < 2pπ–3dπ (Correct)

Same orbital overlap (2p–2p) is strongest

2p–3p is weaker (size mismatch)

2p–3d is even weaker

Correct

(C) 3pπ–3pπ < 3dπ–3dπ (Correct)

d orbitals are more diffused → better overlap than 3p–3p π in this comparison

(D) 3pσ–3pσ > 3pπ–3pπ (Correct)

Sigma bond is always stronger than pi bond