The hybridisation of central atom in the cationic part of N 2 O 5 is sp X while the total number of identical bond angle in the anionic part of N 2 O 5 is Y . Find the value of X Y .

Question

The hybridisation of central atom in the cationic part of N 2 ​ O 5 ​ is sp X while the total number of identical bond angle in the anionic part of N 2 ​ O 5 ​ is Y . Find the value of X Y ​ .

TestHub · Accepted Answer

Structure of N₂O₅

It exists as NO₂⁺ (cation) and NO₃⁻ (anion)

Cationic part: NO₂⁺

Structure: linear (O=N=O⁺)

Hybridization of N = sp

→ $x = 1$

Anionic part: NO₃⁻

Structure: trigonal planar

All O–N–O bond angles are 120°

Total identical bond angles = 3

→ $y = 3$

Final calculation:

$\frac{y}{x} = \frac{3}{1} = 3$

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