Find the total number of correct order(s) according to given properties? (I) H 2 O 2 H 2 O : extent of hydrogen bonding (II) CH 4 SiH 4 GeH 4 SnH 4 : Boiling point (III) Ortho-hy

Question

Find the total number of correct order(s) according to given properties?

(I) $H_{2} O_{2} > H_{2} O$ : extent of hydrogen bonding

(II) $CH_{4} > SiH_{4} > GeH_{4} > SnH_{4}$ : Boiling point

(III) Ortho-hydroxybenzaldehyde > para-hydroxybenzaldehyde : acidic character

(IV) $HF > HCl > HBr > HI$ : heat of vaporization

(V) $H_{2} O > H_{2} Te > H_{2} Se > H_{2} S$ : Melting point

(VI) $H_{2} SO_{4} > Me_{2} SO_{4}$ : Boiling point

TestHub · Accepted Answer

(i) H₂O₂ > H₂O (extent of H-bonding) Correct, because H₂O₂ has two –OH groups and shows more extensive hydrogen bonding.

(ii) CH₄ > SiH₄ > GeH₄ > SnH₄ (boiling point) Incorrect; actual order is CH₄ < SiH₄ < GeH₄ < SnH₄.

(iii) o-Hydroxybenzaldehyde > p-Hydroxybenzaldehyde (acidic character) Correct, as intramolecular H-bonding in ortho compound stabilizes the conjugate base.

(iv) HF > HCl > HBr > HI (heat of vaporization) Correct; HF has strongest H-bonding, hence highest ΔHvap.

(v) H₂O > H₂Te > H₂Se > H₂S (melting point) Correct.

(vi) H₂SO₄ > Me₂SO₄ (boiling point) Incorrect; dimethyl sulfate has a higher boiling point.

Hence, correct orders are (i), (iii) and (iv).

Total number of correct orders = 3.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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