Column-I Column-II (P) BrF 2 − (1) d z 2 -orbital is participated in hybridisation of any one of its central atom (Q) XeF 5 − (2) sp 3 d-hybridised central atom (R) XeO 2 F 2 (3) Non planar

Question

Column-I Column-II (P) BrF 2 − ​ (1) d z 2 ​ -orbital is participated in hybridisation of any one of its central atom (Q) XeF 5 − ​ (2) sp 3 d-hybridised central atom (R) XeO 2 ​ F 2 ​ (3) Non planar with one lone pair on central atom (S) IOF 5 ​ (4) See-saw geometry Code :

TestHub · Accepted Answer

(P) BrF 2 − ​ → (1), (2) Steric number = 5 → sp³d hybridization d-orbitals (like dz²) participate (Q) XeF 5 − ​ → (1) Steric number = 7 → involves d-orbitals dz² orbital participation possible (R) XeO 2 ​ F 2 ​ → (1), (2), (3), (4) Steric number = 5 → sp³d hybridization Contains 1 lone pair → non-planar Geometry becomes see-saw d-orbital participation (S) IOF 5 ​ → (1) Iodine uses d-orbitals in bonding

Column-I	Column-II
(P) $BrF_{2}^{-}$	(1) $d_{z^{2}}$ -orbital is participated in hybridisation of any one of its central atom
(Q) $XeF_{5}^{-}$	(2) sp³d-hybridised central atom
(R) $XeO_{2} F_{2}$	(3) Non planar with one lone pair on central atom
(S) $IOF_{5}$	(4) See-saw geometry Code :

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Options:

(P) $BrF_{2}^{-}$ → (1), (2)

(Q) $XeF_{5}^{-}$ → (1)

(R) $XeO_{2} F_{2}$ → (1), (2), (3), (4)

(S) $IOF_{5}$ → (1)

Doubts & Discussion

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Options:

(P) BrF2−​ → (1), (2)

(Q) XeF5−​ → (1)

(R) XeO2​ F2​ → (1), (2), (3), (4)

(S) IOF5​ → (1)

Doubts & Discussion

(P) $BrF_{2}^{-}$ → (1), (2)

(Q) $XeF_{5}^{-}$ → (1)

(R) $XeO_{2} F_{2}$ → (1), (2), (3), (4)

(S) $IOF_{5}$ → (1)