Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Finding the number of hybridized orbitals (by using the formula) in the central atom to find the hybridization:

$\text{H}=\frac{1}{2}\left(\text{V}+\text{M}-\text{C}+\text{A}\right)$

${{\mathrm{SbCl}}_6}^{-} \Rightarrow \mathrm{H} = \frac{1}{2}(5+6+1)=6, {\mathrm{sp}}^3{\mathrm{d}}^2$ ${}_{}^{}$
${{\mathrm{SnCl}}_6}^{2-} \Rightarrow \mathrm{H} = \frac{1}{2}(4+6+2)=6, {\mathrm{sp}}^3{\mathrm{d}}^2$
${{\mathrm{XeF}}_5}^{+} \Rightarrow \mathrm{H} = \frac{1}{2}(8+5-1)=6, {\mathrm{sp}}^3{\mathrm{d}}^2$
${{\mathrm{IO}}_6}^{5-} \Rightarrow \mathrm{H} = \frac{1}{2}(7+0+5)=6, {\mathrm{sp}}^3{\mathrm{d}}^2$