Consider the following statements ; (I) The hybridisation found in cation of solid PCl 5 is sp 3 . (II) In AB 2 L 2 type the BAB bond angle is always greater than the normal tetrahedral bond ang

Question

Consider the following statements ;

(I) The hybridisation found in cation of solid $PCl_{5}$ is $sp^{3}$ .

(II) In $AB_{2} L_{2}$ type the BAB bond angle is always greater than the normal tetrahedral bond angle.

(III) In $ClO_{3}^{-}, NH_{3}$ and $XeO_{3}$ , the hybridisation and the number of lone pairs on the central atoms are same.

(IV) In $P_{4}$ molecule, there are six $P - P$ bonds and four lone pairs of electrons.

of these statements :

TestHub · Accepted Answer

(I) [ PCl 4 ​ ] + → sp 3 (II) has ≈ 10 2 ∘ bond angle due to lp − lp repulsion, as bond pairs are closer to F -atoms. (III) All have sp 3 hybridisation and one lone pair. (IV)

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