Chemistry - CHEMICAL BONDING Question with Solution | TestHub
ChemistryCHEMICAL BONDINGMOTMedium2 minQB
ChemistryMediumsingle choice
For a homonuclear diatomic with z as bond axis, ignore radial nodes. Count a transverse internuclear nodal plane when present. Inversion is through the bond midpoint. Use the two lists below and choose the INCORRECT complete assignment.
Symmetry code | Meaning |
[a] | bonding, g |
[b] | bonding, u |
[c] | antibonding, u |
[d] | antibonding, g |
List-I | List-II |
|---|---|
[P] σ(2s) | [1] zero nodal planes |
[Q] π(2pₓ) | [2] one nodal plane |
[R] σ*(2) | [3] two nodal planes |
[S] δ(3) |
|
Options:
Answer:
C
Solution:
σ(2s) is bonding gerade with no angular nodal plane. π(2pₓ) is bonding ungerade with the yz nodal plane. σ*(2) has a transverse nodal plane and ungerade symmetry, so R requires 2, c, not 2, d. Bonding δ(3) has xz and yz nodes and is gerade.
Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:MOT
⏱ 2mℹ️ Source: QB
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