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ChemistryCHEMICAL BONDINGMOTMedium2 minQB

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In the formation of $N_{2}^{+}$ from $N_{2}$ , the electron is lost from a

Answer:

Solution:

M.O. configuration of N₂ is:

$σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} π 2 p_{y}^{2} = π 2 p_{z}^{2} σ 2 p_{x}^{2}$ .

M.O. configuration of N₂⁺ is:

$σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} π 2 p_{y}^{2} = π 2 p_{z}^{2} σ 2 p_{x}^{1}$ .

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:MOT

⏱ 2mℹ️ Source: QB

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