Select the CORRECT statement regarding B 2 H 6 . (I) It is not a electron de | TestHub

Passage / Comprehension

The simplest boron hydride known is diborane ( $B_{2} H_{6}$ ). As implied by the mechanism of hydrolysis, diborane and many other light boron hydrides act as Lewis acids, and they are cleaved by reaction with Lewis bases. Two different cleavage patterns have been observed: symmetric cleavage and unsymmetric cleavage. In symmetric cleavage, $B_{2} H_{6}$ is broken symmetrically into two $B H_{3}$ fragments with $NM e_{3}$ . While with $N H_{3}$ , $M e N H_{2}$ , $M e N H_{2}$ results in unsymmetrical cleavage, which is a cleavage leading to an ionic product.

Select the CORRECT statement regarding $B_{2} H_{6}$ .

(I) It is not a electron deficient compound

(II) It involves participation of vacant orbital in hybridization

(III) $sp^{3} - sp^{3} - sp^{3}$ type of overlapping is present

(IV) Bridge bond is longer than terminal bond

(V) Both the boron are $sp^{3}$ hybridized

(VI) $3 c - 4 e^{-}$ bond is not present in the molecule

Answer:

Solution:

(i) and (iii) are incorrect.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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