The observed dipole moment of HCl molecule is 1.03 D . If H − Cl bond distance is 1.275 Å and electronic charge is 4.8 × 1 0 − 10 e.s.u. The % polarity in HCl will be

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Percentage polarity = c a l c u l a t e dd i p o l e m o m e n t o b ser v e dd i p o l e m o m e n t o f m o l ec u l es ​ × 100% Here, the observed dipole moment of HCl = 1.03 D . Calculated dipole moment of HCl = 4.8 × 1 0 − 10 × 1.275 × 1 0 − 8 = 4.8 × 1.275 D . Therefore, % p o l a r i t y = 4.8 × 1.275 1.03 ​ × 100%

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