Chemistry - CHEMICAL BONDING Question with Solution | TestHub

P (XeF₅⁻): Steric Number (SN) = $\frac{8+5+1}{2}=7$, which gives sp³d³ hybridization (3).

Q (XeO₂F₂): Xe forms 4 $\sigma$-bonds and has 1 lone pair (SN = 5), giving sp³d hybridization (2).

R (XeOF₄): Xe forms 5 $\sigma$-bonds and has 1 lone pair (SN = 6), giving sp³d² hybridization (4).

S (XeO₃): Xe forms 3 $\sigma$-bonds and has 1 lone pair (SN = 4), giving sp³ hybridization (1).

Conclusion: The correct matching option is P $\to$ 3; Q $\to$ 2; R $\to$ 4; S $\to$ 1, which corresponds to (A).