Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(P) AlCl₄⁻: Aluminum is $s{p}^3$ hybridized. No d-orbitals are used. (P $\to$ 4)

(Q) SF₄: Sulfur is $s{p}^{3}d$ hybridized (see-saw shape). The d-orbital used in trigonal bipyramidal geometry is $d_{z^2}$. (Q $\to$ 1)

(R) IF₇: Iodine is $s{p}^3{d}^3$ hybridized (pentagonal bipyramidal). It uses $d_{z^2}$, $d_{x^2-y^2}$, and $d_{xy}$ orbitals. Since (2) and (3) are the only remaining options, it matches with $d_{xy}$ from the given list. (R $\to$ 2)

(S) XeF₄: Xenon is $s{p}^3{d}^2$ hybridized (square planar). The d-orbitals used are $d_{z^2}$ and $d_{x^2-y^2}$. (S $\to$ 3)