Chemistry - CHEMICAL BONDING Question with Solution | TestHub
ChemistryCHEMICAL BONDINGWeak ForcesHard2 minQB
ChemistryHardmultiple choice
Consider the planar molecule (NC)₂C=C(CN)₂, where each CN denotes a C≡N group attached through carbon. Ignore conformational distortions. Also compare ideal square-pyramidal IF₅ and trigonal-planar BBr₃. Which statements are FALSE?
Options:(select one or more)
Answer:
C, D
Solution:
The alkene has 1 central σ plus4 C–C σ plus4 C≡N σ=9; its π total is 1+4×2=9, so A is true. Five ligands give5choose2=10 angles; six are basal-pair angles (four90°, two180°) and four apex-basal angles are 90°, so B is true and D false. Symmetric planar BBr₃ has zero permanent dipole despite polar bonds, rejecting C; dispersion and induced effects remain possible.
Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Weak Forces
⏱ 2mℹ️ Source: QB
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