Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMolecules do not exist, SilicatesMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

Column - I Anionic part of Silicate	Column- II Number of oxygen shared per tetrahedral	Column-III Types of Silicate
(I) $(Si_{4} O_{11}^{- 6})_{n}$	(i) 1	(P) Cyclic
(II) $(SiO_{3}^{- 2})_{n}$	(ii) 2	(Q) Amphibole
(III) $(Si_{2} O_{5}^{- 2})_{n}$	(iii) 2.5	(R) Sheet
(IV) $(SiO_{2})_{n}$	(iv) 3	(S) Pyroxene

Select the CORRECT combination.

Answer:

Solution:

In $(S i_{4} O_{11}^{6 -})_{n}$ , each $S i O_{4}$ tetrahedron shares $2.5 O a t o m s$ $\to$ $A m p hib o l e (Q)$ .

$(S i O_{3}^{2 -})_{n}$ has $2 O s ha re d$ $\to$ $P yro x e n e (S)$ .

$(S i_{2} O_{5}^{2 -})_{n}$ has $3 O s ha re d$ $\to$ $S h ee t s i l i c a t e (R)$ .

$(S i O_{2})_{n}$ has $4 O s ha re d$ $\to$ $3 - d im e n s i o na l s i l i c a t e$ .

Therefore, (III) $\to$ (iv) $\to$ (R).

Hence the correct combination is $(A)$ .

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Molecules do not exist, Silicates

⏱ 2mℹ️ Source: QB

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