Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(A) Correct: C₂²⁻ has 14 electrons. Its configuration ends in $(\pi 2p_x{)}^2(\pi 2p_y{)}^2(\sigma 2p_z{)}^2$; since all electrons are paired, it is diamagnetic.

(B) Incorrect: O₂²⁺ (14e⁻) has a bond order of 3, while O₂ (16e⁻) has a bond order of 2. A higher bond order means a shorter bond length.

(C) Correct: Both N₂⁺ (13e⁻) and N₂⁻ (15e⁻) have the same bond order of 2.5, as calculated by $\frac{N_b-N_a}{2}$.

(D) Incorrect: He₂⁺ has a bond order of 0.5, indicating it is more stable and has lower energy than two isolated He atoms.