Chemistry - CHEMICAL BONDING Question with Solution | TestHub

${\mathrm{O}}_2^{-}$(Total electron $=17\left)\right\{$ Bond order $=1.5$, Paramagnetic $\}$

$\sigma 1{ \mathrm{s}}^2,{\sigma }^{\star }1{ \mathrm{s}}^2,\sigma 2{ \mathrm{s}}^2,{\sigma }^{\star }2{ \mathrm{s}}^2,\sigma 2{\mathrm{P}}_z^2,\pi 2{\mathrm{P}}_x^2=\pi 2{\mathrm{P}}_y^2,{\pi }^{*}2{\mathrm{P}}_x^2={\pi }^{*}2{\mathrm{P}}_y^1,{\sigma }^{\star }2{{\mathrm{P}}_z}^0$

Number of unpaired electron $=1$

Bond order $=\frac{n_b-n_a}{2}=\frac{10-7}{2}=1.5$