Consider M.O.T. for the given questions and find the correct statement(s). E 2 → E 2 q B.L. 121 pm 112 pm B.E. 496 pm 643 pm (I) E 2 can have ( σ 2 p ) 2 ( π 2 p ) 4 ( π 2 p ∗ ) 2 configur

Question

Consider M.O.T. for the given questions and find the correct statement(s).

$E_{2} \to E_{2}^{q}$

B.L. 121 pm 112 pm B.E. 496 pm 643 pm

(I) $E_{2}$ can have $(σ_{2 p})^{2} (π_{2 p})^{4} (π_{2 p}^{*})^{2}$ configuration.

(II) $q = +$ ve value.

(III) $E_{2}^{q}$ has more antibonding electrons.

(IV) Bond order of $E_{2} > E_{2}^{q}$ .

TestHub · Accepted Answer

1. E₂ has electronic configuration ( σ 2 p ​ ) 2 ( π 2 p ​ ) 4 ( π 2 p ∗ ​ ) 2 → bond order = 2 2. Bond length of E₂ = 121 pm, bond energy = 496 kJ/mol 3. E₂⁺ (cation, q = +ve) → one electron removed from antibonding orbital 4. Shorter bond length (112 pm) and higher bond energy (643 kJ/mol) observed 5. Fewer antibonding electrons in E₂⁺ → bond order increases to 2.5 6. Statement (III) claiming more antibonding electrons in E₂⁺ 7. Statement (IV) claiming BO(E₂) > BO(E₂⁺) Correct statements: (I) and (II)

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Options:

Doubts & Discussion