Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGVSEPR, Bond Angle, Bond Length, Bond EnergyMedium2 minQB
ChemistryMediummultiple choice

Structure of (pale yellow solid) and are given below

(It is observed that the geometry of nitrogen is planar with its surrounding atoms in structure-I.)

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Select the CORRECT statements:

(A) A maximum of seven atoms may lie in one plane in structure (I).

(B) 10 atoms are sp³-hybridized in structure (I).

(C) 9 d-orbitals are involved in bonding in structure (I).

(D) The S-O bond length of FXeOSO₂F is less than the S-N bond length in FXeN(SO₂F)₂.

Options:(select one or more)

Answer:
A, D
Solution:

Statement A is correct: Since the nitrogen atom has a planar geometry, the Xe–N(S)₂ core lies in a single plane; adjusting the tetrahedral –SO₂F groups allows a maximum of 7 atoms (Xe, N, two S, and one atom from each group) to lie in that same plane.

 

Statement B is incorrect: Only the 2 sulfur atoms are sp³ hybridized in structure (I), whereas nitrogen is sp² hybridized due to its planar geometry.

 

Statement C is incorrect: The number of -orbitals involved in the bonding of the two –SO₂F groups is much fewer than 9.

 

Statement D is correct: Because oxygen has a smaller atomic radius and higher electronegativity than nitrogen, the S–O bond length is naturally shorter than the S–N bond length.

 

Conclusion: The correct options are A and D.

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VSEPR, Bond Angle, Bond Length, Bond Energy
2mℹ️ Source: QB

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