Given below are two statements :
Statement (I) : A $π$ bonding $MO$ has lower electron density above and below the inter-nuclear axis.

Statement (II) : The $π^{*}$ antibonding $MO$ has a node between the nuclei.
In light of the above statements, choose the most appropriate answer from the options given below:

Question

Given below are two statements :
Statement (I) : A $π$ bonding $MO$ has lower electron density above and below the inter-nuclear axis.

Statement (II) : The $π^{*}$ antibonding $MO$ has a node between the nuclei.

In light of the above statements, choose the most appropriate answer from the options given below:

TestHub · Accepted Answer

The pi bonding molecular orbital has a larger electron density above and below the internuclear axis due to the symmetry of the orbital, interference of atomic orbitals, and overlap of atomic orbitals. The electron density is minimum along the internuclear axis due to the nodal plane.

A $π$ bonding molecular orbital has higher electron density above and below inter nuclear axis.

This $π^{*}$ orbital has two nodes: one node is the plane which contains the atoms, and the other node is a plane perpendicular to this, between the two carbon atoms.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Options:

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