Chemistry - CHEMICAL BONDING Question with Solution | TestHub

The central $\mathrm{Xe}$ atom in ${\mathrm{XeO}}_3$ has three bonding domains and one lone pair of electrons. Hence, the electron geometry is tetrahedral and molecular geometry is pyramidal.

${\mathrm{XeO}}_2 {\mathrm{F}}_2$ is trigonal bipyramidal and the shape is a see-saw.

${\mathrm{XeOF}}_4$ is in square pyramidal shape.

So, ${\mathrm{XeF}}_5^{+},{\mathrm{XeO}}_3,{\mathrm{XeO}}_2 {\mathrm{F}}_2$ and ${\mathrm{XeOF}}_4$ have single lone pair on central atom.