Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGIntroduction, ValencyEasy2 minPYQ_2023

ChemistryEasysingle choice

The covalency and oxidation state respectively of boron in ${[{BF}_{4}]}^{-}$ , are

Options:

Answer:

Solution:

Number of covalent bond formed by Boron is $4$ .

${[{BF}_{4}]}^{-}$ Covalency $= 4$

The oxidation state of an element represents the charge it would have if all the bonding electrons were assigned to the more electronegative atom in the bond.

Oxidation number of fluorine is -1

Then,

$B + 4 x (- 1) = - 1 B - 4 = - 1 B = + 3$

Oxidation state $= + 3$ for Boron

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Introduction, Valency

⏱ 2mℹ️ Source: PYQ_2023

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