Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Charge of electron$=1.6\times {10}^{-\mathrm{19 }}\text{C}$
Dipole moment of$\text{HBr}=1.6 \times {10}^{-30}\text{C}\times \text{m}$
Inter-atomic space (distance) =$\text{1}\stackrel{\text{o}}{\text{A}}$
$=1\times {10}^{-10} \mathrm{m}$
Percentage of ionic character in$\text{HBr}$
$=\frac{\mathrm{D}\mathrm{i}\mathrm{p}\mathrm{o}\mathrm{l}\mathrm{e}\mathrm{ }\mathrm{m}\mathrm{o}\mathrm{m}\mathrm{e}\mathrm{n}\mathrm{t}\mathrm{ }\mathrm{o}\mathrm{f}\mathrm{ }\mathrm{H}\mathrm{B}\mathrm{r}\mathrm{ }\times \mathrm{ }100}{\mathrm{i}\mathrm{n}\mathrm{t}\mathrm{e}\mathrm{r-atomic}\mathrm{ }\mathrm{d}\mathrm{i}\mathrm{s}\mathrm{t}\mathrm{a}\mathrm{n}\mathrm{c}\mathrm{e}\mathrm{ }\times \mathrm{ }q}$
$=\frac{1.6\times {10}^{-30}}{1.6\times {10}^{-19}\times {10}^{-10}}\times 100$
$={10}^{-30} \times {10}^{29}\times 100$
$={10}^{-1}\times 100$
$=0.1\times 100$
$=10\%$