Chemistry - CHEMICAL BONDING Question with Solution | TestHub

${\mathrm{O}}_2,{\mathrm{Cu}}^{2+}$ and ${\mathrm{Fe}}^{3+}$ all have unpaired electrons so, they are paramagnetic,

$$\begin{gathered} {\mathrm{O}}_2 \mathrm{has} \mathrm{two} \mathrm{unpaired} \mathrm{electrons} \mathrm{according} \mathrm{to} \mathrm{MOT}, \\ {\mathrm{Cu}}^{2+} \mathrm{has} {\mathrm{d}}^9 \mathrm{configuration} \mathrm{so}, \mathrm{one} \mathrm{unpaired} \mathrm{electron}. \\ {\mathrm{Fe}}^{+3} \mathrm{has} {\mathrm{d}}^5 \mathrm{configuration} \mathrm{so}, 5 \mathrm{unpaired} \mathrm{electrons}. \end{gathered}$$

$\therefore$ Weakly attracted by magnetic field.

$\mathrm{NaCl}$ and ${\mathrm{H}}_2\mathrm{O}$ does not have any unpaired electrons so they are diamagnetic,

$\therefore$ Weakly repelled by magnetic field.