Chemistry - CHEMICAL BONDING Question with Solution | TestHub

$\text{ In }{\mathrm{B}}_2{}^{+}\text{number of electron }=9$

${\mathrm{B}}_2{}^{+}=(\sigma 1 \mathrm{s}{)}^2{\left({\sigma }^{*}1 \mathrm{s}\right)}^2(\sigma 2 \mathrm{s}{)}^2{\left({\sigma }^{\star }2 \mathrm{s}\right)}^2\left(\pi 2{\mathrm{p}}_{\mathrm{x}}{}^1=\pi 2{\mathrm{p}}_{\mathrm{y}}^0\right),$

so unpaired electron $=1$

$\mu =\sqrt{n(n+2)}\mathrm{B.M}$

$\mu =\sqrt{3} \text{ B.M. }=1.73=173\times {10}^{-2}\text{ B.M }$