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Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGWeak ForcesEasy2 minPYQ_2020

ChemistryEasysingle choice

$H_{2} S e$ has higher boiling point than $H_{2} S$ . This is best explained by

Options:

Answer:

Solution:

Both $H_{2} S e$ and $H_{2} S$ are polar but the former has higher dispersion forces due to its higher molecular weight and hence the higher boiling point.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Weak Forces

⏱ 2mℹ️ Source: PYQ_2020

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