Chemistry - CHEMICAL BONDING Question with Solution | TestHub

CO has no unpaired electron while other have (Apply M.O.T)

$\mathrm{\text{E}}\mathrm{\text{n}}\mathrm{\text{e}}\mathrm{\text{r}}\mathrm{\text{g}}\mathrm{\text{y}}\mathrm{\text{l}}\mathrm{\text{e}}\mathrm{\text{v}}\mathrm{\text{e}}\mathrm{\text{l}}\mathrm{\text{F}}\mathrm{\text{o}}\mathrm{\text{r}}\mathrm{\text{m}}\Rightarrow$

$\text{CO }:{\text{like N}}_2;\text{ σ}1{\text{S}}^2<\stackrel{*}{\text{σ}}1{\text{S}}^2<\text{σ}2{\text{S}}^2<\stackrel{*}{\text{π}}2{\text{S}}^2<\text{π}2{\text{P}}_{\text{x}}^2\text{= π}2{\text{P}}_{\text{y}}^2<\text{σ}2{\text{P}}_{\text{z}}^2({\text{NO unpaired e}}^{-})$

${\text{O}}_2:\text{σ}1{\text{S}}^2<\stackrel{*}{\text{σ}}1{\text{S}}^2<\text{σ}2{\text{S}}^2<\stackrel{*}{\text{σ}}2{\text{S}}^2<\text{σ}2{\text{P}}_{\text{z}}^2<\text{π}2{\text{P}}_{\text{x}}^2=\text{π}2{\text{P}}_{\text{y}}^2<\stackrel{*}{\text{π}}2{\text{P}}_{\text{x}}^{\text{1}}\text{= }\stackrel{*}{\text{σ}}2{\text{P}}_{\text{y}}^{\text{1}}\left(2-{\text{unpaired e}}^{-}\right)$

${\text{B}}_2:\text{σ}1{\text{S}}^2<\stackrel{*}{\text{σ}}1{\text{S}}^2<\text{σ}2{\text{S}}^2<\stackrel{*}{\text{σ}}2{\text{S}}^2<\text{π}2{\text{P}}_{\text{x}}^1=\text{π}2{\text{P}}_{\text{y}}^{\text{1}}$( 2− unpaired e − )

$\text{NO }:\text{σ}1{\text{S}}^2<\stackrel{*}{\text{σ}}1{\text{S}}^2<\text{σ}2{\text{S}}^2<\stackrel{*}{\text{σ}}2{\text{S}}^2<\text{π}2{\text{P}}_{\text{x}}^2=\text{π}2{\text{P}}_{\text{y}}^2<\text{σ}2{\text{P}}_{\text{z}}^2<\stackrel{*}{\text{π}}2{\text{P}}_{\text{y}}^{\text{1}}=\stackrel{*}{\text{π}}2{\text{P}}_{\text{x}}^0\left({\text{unpaired e}}^{-}\right)$

have unpaired e- so parametic