Chemistry - CHEMICAL BONDING Question with Solution | TestHub

For polar molecule dipole moment,$\text{μ}$depends upon geometry. Symmetrical molecule is non-polar even through it contains polar bonds. Bond dipole moment of$\text{C}-\text{H}$and$\text{C}-\text{Cl}$bond reinforce on one another.

In${\text{CHCl}}_{\text{3}}$the resultant$\text{C}-\text{H}$and$\text{C}-\text{Cl}$dipoles oppose the resultant of two$\text{C}-\text{Cl}$dipoles, while in${\text{CH}}_{\text{2}}{\text{Cl}}_{\text{2}}$the resultant of$\text{C}-\text{H}$dipoles add to resultant of two$\text{C}-\text{Cl}\text{.}$In case of${\text{CH}}_{\text{3}}\text{Cl}$the resultant of two$\text{C}-\text{H}$dipoles add to the resultant of$\text{C}-\text{H}$and$\text{C}-\text{Cl}$dipoles. Thus dipole moment of${\text{CH}}_{\text{3}}\text{Cl}$is highest among the given compounds.${\text{CCl}}_{\text{4}}$becomes symmetrical and its reduces to zero.